Consider a network using Ethernet and IPv4 (no options field). MTU = 1500 bytes. A UDP segment with payload (data) of 7488 bytes is transmitted. Which ONE of the following correctly gives the total number of fragments and the size of the last fragment (including IPv4 header)?

Correct Answer: (D) 6 fragments, 116 bytesTotal IP datagram size: UDP header (8) + UDP payload (7488) = 7496 bytes + IP header (20) = 7516 bytes total.Max data per fragment: 1500 − 20 = 1480 bytes.Fragments 1–5: 1480 bytes data each = 1500 bytes total per fragment.Remaining data: 7496 − (5×1480) = 7496 − 7400 = 96 bytes.Fragment 6: 96 + 20 (IP header) = 116 bytes. Total fragments = 6.

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