Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at

Q: What is NEET?

NEET is a competitive examination conducted in India. This question is from the 2022 NEET Physics paper.

Q: How can I prepare for NEET Physics?

To prepare for NEET Physics, practice previous year questions (PYQs), understand concepts thoroughly, and solve mock tests regularly. This 2022 question covers Oscillations topic.

Q: What is the difficulty level of this question?

This NEET 2022 Physics question has a medium difficulty level and is marked as an important question.

Q: Where can I find more NEET previous year questions?

You can find more NEET previous year questions on AspirantMitraa. Browse by subject, topic, year, and difficulty level to practice effectively.

Question

Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

Accepted Answer

Correct Answer: B - 11Step-by-step Solution:Time period of a pendulum: T ∝ √L. The ratio of time periods is T₁/T₂ = √(L₁/L₂) = √(121/100) = 11/10, where T₁ corresponds to L₁ = 121 cm (longer, slower pendulum) and T₂ to L₂ = 100 cm (shorter, faster pendulum).For the two pendulums to be back in phase: n₂T₂ = n₁T₁, where n₁ and n₂ are the number of complete oscillations. Substituting: n₂/n₁ = T₁/T₂ = 11/10. The minimum values are n₂ = 11 and n₁ = 10. Therefore, the shorter pendulum (100 cm) completes 11 vibrations while the longer one completes 10.Key Concept: Time period of a simple pendulum: T = 2π√(L/g). Two pendulums are again in phase when they complete whole numbers of oscillations simultaneously.

Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

Master NEET with Our Test Series

More Questions from Oscillations

Frequently Asked Questions

Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

Master NEET with Our Test Series

More Questions from Oscillations

Frequently Asked Questions