Weight (g) of two moles of the organic compound, which is obtained by heating sodium ethanoate with

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Question

Weight (g) of two moles of the organic compound, which is obtained by heating sodium ethanoate with sodium hydroxide in presence of calcium oxide is :

Accepted Answer

Correct Answer: B — 32 gStep-by-step Solution:Reaction: Sodium ethanoate (sodium acetate, CH₃COONa) is heated with soda lime (NaOH + CaO, where CaO prevents the mixture from becoming too corrosive and maintains a dry, free-flowing powder):CH₃COONa + NaOH → CH₄ (methane) + Na₂CO₃This is the decarboxylation (soda lime) reaction. The product is methane (CH₄).Molar mass of CH₄ = 12 + 4(1) = 16 g/molWeight of 2 moles of CH₄ = 2 × 16 = 32 gWhy other options are wrong:Option A (16): This is the mass of only 1 mole of CH₄, not 2 moles.Option C (30): 30 g would be the molar mass of C₂H₆ (ethane) — this is not the product of this reaction.Option D (18): 18 g/mol is the molar mass of water (H₂O) — not the product here.Key Concepts:Soda lime decarboxylation: RCOONa + NaOH → R–H + Na₂CO₃ (where soda lime = NaOH + CaO). The carboxylate loses one CO₂ group → the alkane with one carbon less.CH₃COONa (sodium acetate) → CH₄ (methane): The acetate (2-carbon) loses –COO to give methane (1-carbon).General rule: CₙH₂ₙ₊₁COONa + NaOH → CₙH₂ₙ₊₂ + Na₂CO₃.This method is used in the laboratory to prepare lower alkanes from sodium salts of carboxylic acids.

Weight (g) of two moles of the organic compound, which is obtained by heating sodium ethanoate with sodium hydroxide in presence of calcium oxide is :

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Weight (g) of two moles of the organic compound, which is obtained by heating sodium ethanoate with sodium hydroxide in presence of calcium oxide is :

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