Which amongst the following options are correct graphical representation of Boyle's law?

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Question

Which amongst the following options are correct graphical representation of Boyle's law?

Accepted Answer

Correct Answer: B — P vs 1/V is a straight line through originStep-by-step Solution:Boyle's Law: At constant temperature and fixed amount of gas, the pressure (P) is inversely proportional to the volume (V): P ∝ 1/V, or P × V = constant (k).Therefore: P = k × (1/V). This is the equation of a straight line (y = mx) if we plot P (y-axis) vs 1/V (x-axis), passing through the origin with slope k.Correct plots for Boyle's law at constant T:P vs 1/V: straight line through origin ✓P vs V: hyperbola (rectangular hyperbola) ✓PV vs P: horizontal straight line (PV = k = constant) ✓log P vs log V: straight line with slope −1 ✓Why other options are wrong:Option A (P vs V straight line through origin): This would imply P ∝ V, i.e., PV² = constant — this is NOT Boyle's law. P vs V in Boyle's law gives a hyperbola, not a straight line.Option C (PV vs P non-horizontal curve): For an ideal gas obeying Boyle's law, PV = constant, so PV vs P should be a horizontal straight line. A curve would violate Boyle's law.Option D (V vs T straight line): This represents Charles's Law (V ∝ T at constant P), not Boyle's law.Key Concepts:Boyle's Law: P ∝ 1/V at constant T, n. PV = k.Charles's Law: V ∝ T at constant P, n.Gay-Lussac's Law: P ∝ T at constant V, n.Combined: Ideal Gas Law: PV = nRT (R = 8.314 J mol⁻¹ K⁻¹).

Which amongst the following options are correct graphical representation of Boyle's law?

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Which amongst the following options are correct graphical representation of Boyle's law?

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