The work functions of Caesium (Cs), Potassium (K) and Sodium (Na) are 2.14 eV, 2.30 eV and 2.75 eV r

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Question

The work functions of Caesium (Cs), Potassium (K) and Sodium (Na) are 2.14 eV, 2.30 eV and 2.75 eV respectively. If incident electromagnetic radiation has an incident energy of 2.20 eV, which of these photosensitive surfaces may emit photoelectrons?

Accepted Answer

Correct Answer: A — Cs onlyStep-by-step Solution:For photoelectric emission: photon energy (E) must be ≥ work function (φ)Incident energy = 2.20 eVCs: φ = 2.14 eV Emission occurs ✓ (KEmax = 2.20 − 2.14 = 0.06 eV)K: φ = 2.30 eV > 2.20 eV → No emission ✗Na: φ = 2.75 eV > 2.20 eV → No emission ✗∴ Only Cs emits photoelectrons.Key Concepts:Photoelectric effect condition: Ephoton ≥ φ (work function). If E Maximum KE of emitted electron: KEmax = Ephoton − φ = hν − φThreshold frequency: ν₀ = φ/h. Below this frequency, no emission.Lower work function → easier emission (Cs, K, Na are alkali metals with low work functions).

The work functions of Caesium (Cs), Potassium (K) and Sodium (Na) are 2.14 eV, 2.30 eV and 2.75 eV respectively. If incident electromagnetic radiation has an incident energy of 2.20 eV, which of these photosensitive surfaces may emit photoelectrons?

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The work functions of Caesium (Cs), Potassium (K) and Sodium (Na) are 2.14 eV, 2.30 eV and 2.75 eV respectively. If incident electromagnetic radiation has an incident energy of 2.20 eV, which of these photosensitive surfaces may emit photoelectrons?

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