The highest number of helium atoms is in: (1) 4 mol of helium (2) 4 u of helium (3) 4 g of helium (4

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Question

The highest number of helium atoms is in: (1) 4 mol of helium (2) 4 u of helium (3) 4 g of helium (4) 2.271098 L of helium at STP

Accepted Answer

Correct Answer: a — 4 mol of heliumStep-by-step Solution:The number of atoms is calculated using Avogadro's number (6.022 × 10²³ atoms/mol). For each option:a: 4 mol of He → number of atoms = 4 × 6.022 × 10²³ = 2.4088 × 10²⁴ atoms.b: 4 u (atomic mass unit) is the mass of a single helium atom (since the atomic mass of He is 4 u). Thus, it contains exactly 1 atom.c: 4 g of He → molar mass of He is 4 g/mol, so 4 g corresponds to 1 mol → number of atoms = 6.022 × 10²³.d: 2.271098 L of He at STP → at STP, 1 mole of gas occupies 22.4 L. Therefore, moles = 2.271098 / 22.4 ≈ 0.1014 mol → number of atoms ≈ 0.1014 × 6.022 × 10²³ = 6.1 × 10²² atoms.Clearly, 4 mol of helium contains the highest number of atoms.Key Concepts: Mole concept, Avogadro's number, STP conditions, atomic mass unit (u) vs gram, conversion between moles, mass, volume, and number of particles.

The highest number of helium atoms is in: (1) 4 mol of helium (2) 4 u of helium (3) 4 g of helium (4) 2.271098 L of helium at STP

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The highest number of helium atoms is in: (1) 4 mol of helium (2) 4 u of helium (3) 4 g of helium (4) 2.271098 L of helium at STP

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