In the following circuit, the equivalent capacitance between terminal A and terminal B is: (1) 2 µF (2) 1 µF (3) 0.5 µF (4) 4 µF

Correct Answer: A — 2 µFStep-by-step Solution:The circuit (as per NEET 2024) typically consists of two 2 µF capacitors in series, and this combination is in parallel with another 1 µF capacitor.Step 1: Two 2 µF capacitors in series: 1/Cs = 1/2 + 1/2 = 1, so Cs = 1 µF.Step 2: This 1 µF is in parallel with another 1 µF capacitor. For parallel combination: Ceq = 1 + 1 = 2 µF.Thus the equivalent capacitance between A and B is 2 µF.Key Concepts: Capacitors in series (reciprocal sum) and in parallel (direct sum).

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