Two bodies A and B of same mass undergo completely inelastic one-dimensional collision. The body A moves with velocity v1 while body B is at rest before the collision. The velocity of the system after the collision is v2. The ratio v1 : v2 is: (1) 1 : 2 (2) 2 : 1 (3) 4 : 1 (4) 1 : 4

Correct Answer: B — 2 : 1Step-by-step Solution:In a completely inelastic one-dimensional collision, the two bodies stick together after collision. Conservation of linear momentum gives:Initial momentum = m v1 + m × 0 = m v1.Final momentum = (m + m) v2 = 2m v2.Equating: m v1 = 2m v2 ⇒ v1 = 2 v2 ⇒ v1 : v2 = 2 : 1.Key Concepts: Conservation of linear momentum, perfectly inelastic collision.

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Two bodies A and B of same mass undergo completely inelastic one-dimensional collision. The body A moves with velocity v1 while body B is at rest before the collision. The velocity of the system after the collision is v2. The ratio v1 : v2 is: (1) 1 : 2 (2) 2 : 1 (3) 4 : 1 (4) 1 : 4

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Two bodies A and B of same mass undergo completely inelastic one-dimensional collision. The body A moves with velocity v1 while body B is at rest before the collision. The velocity of the system after the collision is v2. The ratio v1 : v2 is: (1) 1 : 2 (2) 2 : 1 (3) 4 : 1 (4) 1 : 4

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