Identify the correct orders against the property mentioned
A. H2O NH3 CHCl3 – dipole moment
B. X

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Question

Identify the correct orders against the property mentioned
A. H2O > NH3 > CHCl3 – dipole moment
B. XeF4 > XeO3 > XeF2 – number of lone pairs on central atom
C. O–H > C–H > N–O – bond length
D. N2 > O2 > H2 – bond enthalpy
Choose the correct answer from the options given below:
(1) B, C only
(2) A, D only
(3) B, D only
(4) A, C only

Accepted Answer

Correct Answer: B — A, D onlyStep-by-step Solution:A. H₂O > NH₃ > CHCl₃ (dipole moment) — TRUE ✓H₂O = 1.85 D; NH₃ = 1.47 D; CHCl₃ = 1.04 D. Correct order.B. XeF₄ > XeO₃ > XeF₂ (lone pairs) — FALSE ✗Lone pairs: XeF₄ = 2; XeO₃ = 1; XeF₂ = 3. Correct order should be XeF₂ > XeF₄ > XeO₃. The given order is wrong.C. O–H > C–H > N–O (bond length) — FALSE ✗Actual bond lengths: N–O (~140 pm) > C–H (~109 pm) > O–H (~96 pm). Correct order is N–O > C–H > O–H. Given order is the reverse — FALSE.D. N₂ > O₂ > H₂ (bond enthalpy) — TRUE ✓N₂ (triple bond) = 946 kJ/mol; O₂ (double bond) = 498 kJ/mol; H₂ (single bond) = 436 kJ/mol. Correct order.Key Concepts:Dipole moment (μ): μ = q × d. Net dipole depends on both bond polarity and molecular geometry.Lone pairs on Xe: XeF₂: 3 LP, XeF₄: 2 LP, XeOF₄: 1 LP, XeO₃: 1 LP, XeF₆: 1 LP.Bond length: Inversely related to bond order. O–H (single, small atoms) Bond enthalpy: Triple > double > single bond. N≡N is exceptionally strong.

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