A 800 turn coil of effective area 0.05 m² is kept perpendicular to a magnetic field 5 × 10−5 T. When

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Question

A 800 turn coil of effective area 0.05 m² is kept perpendicular to a magnetic field 5 × 10−5 T. When the plane of the coil is rotated by 90° around any of its coplanar axis in 0.1 s, the emf induced in the coil will be:

Accepted Answer

Correct Answer: A — 0.02 VKey Concept: By Faraday's law, induced emf = rate of change of magnetic flux linkage.|ε| = N × |ΔΦ/Δt| = N × |Φf − Φi| / ΔtStep-by-step Solution:Given: N = 800, A = 0.05 m², B = 5 × 10−5 T, Δt = 0.1 sInitial state: coil perpendicular to B means the normal to the coil is parallel to B (θ = 0°):Φi = BA cos 0° = 5 × 10−5 × 0.05 × 1 = 2.5 × 10−6 WbAfter 90° rotation: the coil plane becomes parallel to B (θ = 90°):Φf = BA cos 90° = 0Total flux linkage change: NΔΦ = N(Φi − Φf) = 800 × 2.5 × 10−6 = 2 × 10−3 WbInduced emf: |ε| = NΔΦ/Δt = 2 × 10−3 / 0.1 = 0.02 V

A 800 turn coil of effective area 0.05 m² is kept perpendicular to a magnetic field 5 × 10−5 T. When the plane of the coil is rotated by 90° around any of its coplanar axis in 0.1 s, the emf induced in the coil will be:

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A 800 turn coil of effective area 0.05 m² is kept perpendicular to a magnetic field 5 × 10−5 T. When the plane of the coil is rotated by 90° around any of its coplanar axis in 0.1 s, the emf induced in the coil will be:

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