The magnetic energy stored in an inductor of inductance 4 μH carrying a current of 2 A is

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Question

The magnetic energy stored in an inductor of inductance 4 μH carrying a current of 2 A is

Accepted Answer

Correct Answer: D — 8 μJStep-by-step Solution:Energy stored in an inductor:U = ½LI²L = 4 μH = 4 × 10⁻⁶ H, I = 2 AU = ½ × 4 × 10⁻⁶ × (2)² = ½ × 4 × 10⁻⁶ × 4 = 8 × 10⁻⁶ J = 8 μJWhy other options are wrong:A (4 μJ): This would be for I = 1 A (U = ½ × 4×10⁻⁶ × 1 = 2×10⁻⁶... actually for I=√2 A).B (4 mJ) and C (8 mJ): milli-joule scale is 1000× too large — likely confusion between μH and mH.Key Concepts:Energy stored in inductor: U = ½LI² (analogous to ½kx² for spring)Energy is stored in the magnetic field of the inductor.Unit check: L in H, I in A → U in joules (J). 1 μH = 10⁻⁶ H → U in μJ.

The magnetic energy stored in an inductor of inductance 4 μH carrying a current of 2 A is

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